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<title>Problem 1311. -- 最优压缩 -- 衡阳八中OJ离线版-2012-02-29</title><center><h2>1311: 最优压缩</h2><span class=green>Time Limit: </span>10 Sec&nbsp;&nbsp;<span class=green>Memory Limit: </span>162 MB<br><span class=green>Submit: </span>30&nbsp;&nbsp;<span class=green>Solved: </span>18<br>[<a href='submitpage.php?id=1311'>Submit</a>][<a href='problemstatus.php?id=1311'>Status</a>][<a href='bbs.php?id=1311'>Discuss</a>]</center><h2>Description</h2><div class=content><img border="0" src="images/1311.jpg">

其中:
Auv是与Aij相邻的像素(为了简化,认为(i-1,j),(i+1,j,(i,j-1),(i,j+1)为相邻元素);
Wij取值0或者1,表示Aij修改后取V0或者V1.
E的定义直观上的理解是,当修改了A之后,各像素上的值与原来的值相差了多少,以及相邻的像素对比程度的变化.为了图像的保真度,我们希望E的值越小越好.

</div><h2>Input</h2><div class=content>第一行二个整数N,M(1<=N,M<=35)
第二行二个整数V0,V1
接下来N行M列,对应矩阵元素Aij

</div><h2>Output</h2><div class=content>一个数E,表示最小可能的估价值
</div><h2>Sample Input</h2>
			<div class=content><span class=sampledata>1 2<br />
0 255<br />
10 20<br />
<br />
</span></div><h2>Sample Output</h2>
			<div class=content><span class=sampledata>30</span></div><h2>HINT</h2>
			<div class=content><p></p></div><h2>Source</h2>
			<div class=content><p><a href='problemset.html?search='></a></p></div><center>[<a href='submitpage.php?id=1311'>Submit</a>][<a href='problemstatus.php?id=1311'>Status</a>][<a href='bbs.php?id=1311'>Discuss</a>]</center>﻿<br>

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